Centrifugation
Learning Outcomes
General Idea
Feed added to spinning bowl
Sedimentation of particles occurs in centrifugal field
Flow is upwards at a particular rate which determines residence time in device
Separation happens if sedimentation velocity is high enough for particle to reach side of bowl within residence time
Large particles have higher settling velocities than small particles
Both large and small are still particles, have small Reynolds no.s (<1) and obey Stokes’ Law
The Centrifuge
Separation of milk into skimmed milk and cream is done with a centrifuge
Centrifugal Motion
Compared to gravity
mg
Acceleration constant
In direction of earth
Equilibrium velocity reached
Terminal velocity given by:
mrω2
Acceleration increases with r
Acceleration increases with ω
Away from axis of rotation
Equilibrium velocity never reached
Instantaneous velocity:
Sigma Factor
The capacity of a centrifuge is defined by Σ
Q is the throughput (m3/s) at which all particles with a terminal velocity ≥ uT (m/s) are retained
Σ has units of m2 and is equivalent to the cross sectional area of a thickener with the same capacity
Activity – Determine Σ
The contents of a fermenter are discharged to a centrifuge
Volume of material is 100 m3
Centrifugation time is 5 hrs
Particle size is 3 mm – all particles of this size are separated
Density of solid phase 1090 kg/m3
Cell free liquid density 1025 kg/m3
Cell free liquid viscosity 0.005 Pa.s
Calculate the capacity factor, Σ
Bowl Centrifuge
Sigma Factor – Bowl Centrifuge
For the bowl centrifuge:
ω is the angular velocity (rad/s)
R is the outer radius of the bowl (m)
rc is the radius of the clarified discharge weir (m)
H is the height of the bowl (m)
r is the inner radius of the liquid in the bowl (m)
g is the acceleration due to gravity (m/s2)
A long thin bowl gives good separation
The Disc Stack Centrifuge
Benefit of Discs
Disc Stack Centrifuge Capacity
For the disc stack centrifuge:
ω is the angular velocity (rad/s)
n is the number of discs
R is the outer radius of the discs (m)
r is the inner radius of the discs (m)
θ is the angle between disc and vertical (rad)
g is the acceleration due to gravity (m/s2)
Activity
What is the capacity of the following disc stack centrifuge?
No. of discs = 400
Space between discs is 0.01 m
Inner radius = 0.05 m
Outer radius = 0.20 m
Half vertical angle = 45°
Rotational speed = 4500 rpm
What effect does an increase in diameter have on the capacity?
What diameter is needed for the previous example?
Decanter Centrifuge
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